(2x^3-5x^2+5x+4)/(2x-5)

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Solution for (2x^3-5x^2+5x+4)/(2x-5) equation:


D( x )

2*x-5 = 0

2*x-5 = 0

2*x-5 = 0

2*x-5 = 0 // + 5

2*x = 5 // : 2

x = 5/2

x in (-oo:5/2) U (5/2:+oo)

(2*x^3-(5*x^2)+5*x+4)/(2*x-5) = 0

(2*x^3-5*x^2+5*x+4)/(2*x-5) = 0

2*x^3-5*x^2+5*x+4 = 0

2*x^3-5*x^2+5*x+4 = 0

{ 1, -1, 2, -2, 4, -4 }

1

x = 1

2*x^3-5*x^2+5*x+4 = 6

1

-1

x = -1

2*x^3-5*x^2+5*x+4 = -8

-1

2

x = 2

2*x^3-5*x^2+5*x+4 = 10

2

-2

x = -2

2*x^3-5*x^2+5*x+4 = -42

-2

4

x = 4

2*x^3-5*x^2+5*x+4 = 72

4

-4

x = -4

2*x^3-5*x^2+5*x+4 = -224

-4

{ 1/2, -1/2, -1/2, 1/2, 2/2, -2/2, -2/2, 2/2, 4/2, -4/2, -4/2, 4/2 }

1/2

x

1/2

2*x^3-5*x^2+5*x+4 = 5.5

1/2

-1/2

x

-1/2

2*x^3-5*x^2+5*x+4 = 0

-1/2

x+1/2

2*x^2-6*x+8

2*x^3-5*x^2+5*x+4

x+1/2

-2*x^3-x^2

5*x-6*x^2+4

6*x^2+3*x

8*x+4

-8*x-4

0

2*x^2-6*x+8 = 0

DELTA = (-6)^2-(2*4*8)

DELTA = -28

DELTA < 0

x in { -1/2}

x+1/2 = 0

(x+1/2)/(2*x-5) = 0

x+1/2 = 0 // - 1/2

x = -1/2

x = -1/2

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